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๊ด€๋ฆฌ ๋ฉ”๋‰ด

Data Science LAB

[Python] ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค ์ฝ”๋”ฉํ…Œ์ŠคํŠธ ์—ฐ์Šต level 3 (์•ผ๊ทผ ์ง€์ˆ˜) ๋ณธ๋ฌธ

๐Ÿ“ Coding Test/Programmers

[Python] ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค ์ฝ”๋”ฉํ…Œ์ŠคํŠธ ์—ฐ์Šต level 3 (์•ผ๊ทผ ์ง€์ˆ˜)

ใ…… ใ…œ ใ…” ใ…‡ 2023. 1. 17. 02:04
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1. ๋ฌธ์ œ ์„ค๋ช…

ํšŒ์‚ฌ์› Demi๋Š” ๊ฐ€๋”์€ ์•ผ๊ทผ์„ ํ•˜๋Š”๋ฐ์š”, ์•ผ๊ทผ์„ ํ•˜๋ฉด ์•ผ๊ทผ ํ”ผ๋กœ๋„๊ฐ€ ์Œ“์ž…๋‹ˆ๋‹ค. ์•ผ๊ทผ ํ”ผ๋กœ๋„๋Š” ์•ผ๊ทผ์„ ์‹œ์ž‘ํ•œ ์‹œ์ ์—์„œ ๋‚จ์€ ์ผ์˜ ์ž‘์—…๋Ÿ‰์„ ์ œ๊ณฑํ•˜์—ฌ ๋”ํ•œ ๊ฐ’์ž…๋‹ˆ๋‹ค. Demi๋Š” N์‹œ๊ฐ„ ๋™์•ˆ ์•ผ๊ทผ ํ”ผ๋กœ๋„๋ฅผ ์ตœ์†Œํ™”ํ•˜๋„๋ก ์ผํ•  ๊ฒ๋‹ˆ๋‹ค.Demi๊ฐ€ 1์‹œ๊ฐ„ ๋™์•ˆ ์ž‘์—…๋Ÿ‰ 1๋งŒํผ์„ ์ฒ˜๋ฆฌํ•  ์ˆ˜ ์žˆ๋‹ค๊ณ  ํ•  ๋•Œ, ํ‡ด๊ทผ๊นŒ์ง€ ๋‚จ์€ N ์‹œ๊ฐ„๊ณผ ๊ฐ ์ผ์— ๋Œ€ํ•œ ์ž‘์—…๋Ÿ‰ works์— ๋Œ€ํ•ด ์•ผ๊ทผ ํ”ผ๋กœ๋„๋ฅผ ์ตœ์†Œํ™”ํ•œ ๊ฐ’์„ ๋ฆฌํ„ดํ•˜๋Š” ํ•จ์ˆ˜ solution์„ ์™„์„ฑํ•ด์ฃผ์„ธ์š”.

 

 

 

 

2. ์ œํ•œ ์‚ฌํ•ญ

works๋Š” ๊ธธ์ด 1 ์ด์ƒ, 20,000 ์ดํ•˜์ธ ๋ฐฐ์—ด์ž…๋‹ˆ๋‹ค.
  • works์˜ ์›์†Œ๋Š” 50000 ์ดํ•˜์ธ ์ž์—ฐ์ˆ˜์ž…๋‹ˆ๋‹ค.
  • n์€ 1,000,000 ์ดํ•˜์ธ ์ž์—ฐ์ˆ˜์ž…๋‹ˆ๋‹ค.

 

 

 

 

3. ๋‚ด ํ’€์ด 

import heapq
def solution(n, works):
    works.sort(reverse=True)
    works = [-x for x in works if x>0]
    for i in range(n):
        w = heapq.heappop(works)
        if w <= -1:
            heapq.heappush(works,w+1)
        else:
            heapq.heappush(works,w)
        
    return sum([x**2 for x in works])

์–‘์ˆ˜ ๊ฐ’์„ ์Œ์ˆ˜๊ฐ’์œผ๋กœ ๋ณ€๊ฒฝํ•œ ๋’ค ์ตœ์†Œ ํž™ ์‚ฌ์šฉ

 

 

 

 

 

4. ๋‹ค๋ฅธ ์‚ฌ๋žŒ ํ’€์ด 

from heapq import heapify, heappush, heappop
def solution(n, works):
    heapify(works := [-i for i in works])
    for i in range(min(n, abs(sum(works)))):
        heappush(works, heappop(works)+1)
    return sum([i*i for i in works])
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